Japan vs Sweden: 2.5.1b Number: Value, per capita
Japan
0 No per person
in 2025
Sweden
0 No per person
in 2025
Japan rank
153rd
Sweden rank
151st
2.5.1b Number: Value, per capita over time
- Japan
- Sweden
How they compare
Sweden currently reports 0 No per person against 0 No per person in Japan, a difference of 0 No per person.
That makes Sweden's figure about 1.1 times Japan's.
Across all 26 years both countries report, Sweden has been ahead every year.
Japan ranks 153rd and Sweden ranks 151st of 167 countries.
Sweden has averaged higher in every one of the 3 decades both report.
Head to head by decade
| Decade | Japan | Sweden | Difference | Ahead |
|---|---|---|---|---|
| 2000s | 0 No per person | 0 No per person | 0 No per person | Sweden |
| 2010s | 0 No per person | 0 No per person | 0 No per person | Sweden |
| 2020s | 0 No per person | 0 No per person | 0 No per person | Sweden |
Averages of every year both report within each decade.
Frequently asked questions
- Which has higher 2.5.1b number of transboundary breeds (including extinct ones), Japan or Sweden?
- Sweden, at 0 No per person against 0 No per person in Japan as of 2025.
- What is the difference in 2.5.1b number of transboundary breeds (including extinct ones) between Japan and Sweden?
- 0 No per person, with Sweden ahead.
- How many years of comparable data are there for Japan and Sweden?
- 26 years are reported by both, from 2000 to 2025.
- How do Japan and Sweden rank globally for 2.5.1b number of transboundary breeds (including extinct ones)?
- Japan ranks 153rd and Sweden ranks 151st of 167 countries.
- Where does this data come from?
- Statizoid (derived), published as 2.5.1b Number of transboundary breeds (including extinct ones) β Value, per capita. Statizoid refreshes it automatically from the source and publishes the full history for both places.
Individual pages
About this data
2.5.1b Number of transboundary breeds (including extinct ones) β Value divided by Population, total, matched on country and year. Neither publisher issues this ratio as a series; it is computed here from both.